sin2θ=2sinθcosθを使います。
(1)は2sinθcosθ=cosθなのでcosθ=0のとき、すなわち
π/2、3π/2
またcosθ≠0のとき2sinθ=1なのでθ=π/6 、5π/6
(2)も同様です
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sin2θ=2sinθcosθを使います。
(1)は2sinθcosθ=cosθなのでcosθ=0のとき、すなわち
π/2、3π/2
またcosθ≠0のとき2sinθ=1なのでθ=π/6 、5π/6
(2)も同様です
Users viewing this question
are also looking at these questions 😉
