Answers
展開してaについて降べきの順に整理する
=(b-c)a²-(b²-c²)a+bc(b-c)
=(b-c)a²-(b+c)(b-c)a+bc(b-c)
共通因数でくくる
=(b-c)(a²-(b+c)a+bc)
=(b-c)(a-b)(a-c)
これでもいいけど格好よくするなら
=-(a-b)(b-c)(c-a)
Were you able to resolve your confusion?
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