✨ Best Answer ✨
(sinθ+cosθ)²·=(√6/2)²
sinθ²+cosθ²+2sinθcosθ=3/2
sin2θ=2sinθcosθ、cosθ²=1-sinθ²より
sinθ²+1-sinθ²+sin2θ=3/2
sin2θ =1/2
2θ=π/6、5π/6
θ=π/12、5π/12
✨ Best Answer ✨
(sinθ+cosθ)²·=(√6/2)²
sinθ²+cosθ²+2sinθcosθ=3/2
sin2θ=2sinθcosθ、cosθ²=1-sinθ²より
sinθ²+1-sinθ²+sin2θ=3/2
sin2θ =1/2
2θ=π/6、5π/6
θ=π/12、5π/12
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