Physics
Senior High
物理の電磁気です。
面積S,極板間の距離dの平行平板コンデンサーがあり、両端の電位差はVである。ε0=8.9×10^-12,μ0=1.3×10-6のとき、答えは8.9×10^-12・V/dで合ってますか？
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