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直角三角形を書いてtanθ=√5の三角形を書くと、
斜辺が√6で他の2辺が1、√5の三角形より
sinθ =√5/√6 cosθ =1/√6
また
(sinθ-cosθ)^2=sin^2θ+cos^2θ-2sinθcosθ なので

(sinθ-cosθ)^2=1-√5/3
       =3-√5/3 よって答えは1です。

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