Chemistry
Senior High
どうやったら12.011がでますか?
10cm³
88
IV
14
7
111
-98.9 %-
¹2C
相対質量=12
炭素の原子量=12x
20.0% 0 10
98.9
100
+1.1%
Top 13C
+ 13 x
相対質量 = 13
1.1 Or
= 12.011
100g
9
解
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