Mathematics
Senior High
Solved
数Ⅲの三角関数の極限の問題です。
このまるで囲ったxはどこに行ったのでしょうか?
教えてください🙇♀️🙏
10 lim
xsin x
x-0 cos3x-1
= lim
x->0
-
= lim
x->0
= lim
x→0
=
= lim
x-0
xsin x(cos3x + 1)
cos23x - 1
{-1. (sin x).(-
(sinx)
2
1-1-1-(-/-)² ・(1+
xsin x(cos3x+1)
(cos3x - 1)(cos3x+1)
limsin x (cos3x + 1)
x->0
- sin ²3x
=
3x 2
(5 -)². (cos3x + 1)}
sin 3x
1
sin 3x
3x
2
-3²7
9
2
(cos3x + 1)
Answers
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丸でかこったxは割られて消えます。