✨ Best Answer ✨
1/2log2⁻¹-3/2log12¹‘³+log2³‘²
=-1/2log2-1/2(log2²+log3)+3/2log2
=-1/2log2-log2-1/2log3+3/2log2
=-1/2log3
✨ Best Answer ✨
1/2log2⁻¹-3/2log12¹‘³+log2³‘²
=-1/2log2-1/2(log2²+log3)+3/2log2
=-1/2log2-log2-1/2log3+3/2log2
=-1/2log3
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