Mathematics
Senior High
こっちも解答ではないのですか?
1
05
[6] sir
[3] tan0=√3 s
101: **
(n
[3] P(cos0, sin0)
は右図. よって
0= π
=/7/8/+
=+nπ
(nは整数) .
2
#1
↑
0 = = =+N²²₁ +²x+hx
4
3
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