Mathematics
Senior High
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解答は3です。
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(5) 2loga3√7+loga //
100
(6)* loga√3
halt
8
(5) 2 log = 3√ + log = 7/7/7
3
37
3
2
log² (3√17) ² + logs +
3
2 log 3 3.7² + log = 7
3
2
log = (3.1² ) ² + log₁ ²7
2
log z( 3 ) ² + log = 77
3
3
2 + log3 7 + log 37
t
= 2 + logan + logz 3 - 04/1
=2+
log 3 3
(1
Answers
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