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1つの内角の大きさが180×3/5=108°
AB=BCの二等辺三角形より、∠BAC=∠BCA=(180-108)÷2=36°
同様に、∠CBD=∠CDB=36°
よって、∠ABP=108-36=72°、∠APB=36+36=72°

nana

ありがとうございます!!((🙇‍♀️✨

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