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√3+m=1-√3m
m(1+√3)=1-√3
m=(1-√3)/(1+√3)={(1-√3)/(1+√3)}×{(1-√3)/(1-√3)}=(1-√3)²/(1-3)=-(√3-1)²/2
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√3+m=1-√3m
m(1+√3)=1-√3
m=(1-√3)/(1+√3)={(1-√3)/(1+√3)}×{(1-√3)/(1-√3)}=(1-√3)²/(1-3)=-(√3-1)²/2
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are also looking at these questions 😉
