Mathematics
Senior High
この変形どうなっているんでしょうか
5-6
A₁₁
2
n
n
an
n
2n
12
(1 + J) (1+
n
2
22
2
n
·(1+
2
n
n
a₁ = (n² + 1² ) ( n² + 2²² ) ... (n² + n²)
n
Answers
No answer yet
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ⅰ】第一章 数と式～整式・実数・不等式～
8980
117
詳説【数学Ⅰ】第二章 ２次関数（後半）～最大・最小・不等式～
6128
25
数学ⅠA公式集
5730
20
詳説【数学Ⅱ】第３章 三角関数（前半）～一般角の三角関数～
4913
18