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✨ Best Answer ✨

(2)
n-3
n×(n-3)
n(n-3)/2

(4)
nC2-n

(5)
nC2-2n
=n×(n-1)/2×1-n
=(n²-n)/2-2n/2
=(n²-3n)/2
=n(n-3)/2

Sepia

早急の回答ありがとうございました😊
助かりました!

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