Mathematics
Senior High
Solved
どういう変形なのか教えて欲しいです。
1
(3) y=-
x
√x²+1
[C
(1+x2)2
1.√x²+1-x
2
(3) y' =
||
2
2x
2√√√x²+1
(√√x²+1) 2
x²+1-x2
2
(x²+1)√x²+1
1
2
(x²+1)√√√x²+1
50 AE
+74
Answers
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理解出来ました!