Mathematics
Senior High
Solved
この式の続きが３n（ｎ－１）になるのですが解き方が分かりません。教えて欲しいです🙇🏻
"l
n-1
(2) 6k
Σ6k
k=1
n-1
=
6Σk
k=1
= 6 x = (n-1) { (n-1) +1}
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理解出来ました。ありがとうございました🙇🏻