Mathematics
Senior High
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一般項を求める時、
bn＝（−2）×（−2）n−1乗が（−2）n乗になるのはなぜですか？？
bn＝−2,4,−8,16…です！
至急お願いします
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一般項を求める時、
bn＝（−2）×（−2）n−1乗が（−2）n乗になるのはなぜですか？？
bn＝−2,4,−8,16…です！
至急お願いします
Users viewing this question
are also looking at these questions 😉
