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2はおいておきます。

sin(π/3)=cos(π/2-π/3)
    =cos(π/6)
cos(π/3)=sin(π/2-π/3)
    =sin(π/6)
より、
sin(π/3)+icos(π/3)
=cos(π/6)+isin(π/6)
だから、
2(cos(π/6)+isin(π/6)) になります。 

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