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✨ Best Answer ✨

θの範囲
0≦θ<2π  ー①
①の範囲ーπ/3を全体に足すと
ーπ/3≦θーπ/3<2πーπ/3
2πーπ/3=6π/3ーπ/3=5π/3であるから
ーπ/3≦θーπ/3<5π/3
θーπ/3=tと置いているから
ーπ/3≦t<5π/3

質問があれば聞いて下さい。

tepo

ありがとうございます!!

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