(a+b-c+d)(a-b+c-d)
={a+(b-c+d)}{a-(b-c+d)}
=a²-(b-c+d)²
=a²-(b²+c²+d²-2bc+2bd-2cd)
=a²-b²-c²-d²+2bc-2bd+2cd
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(a+b-c+d)(a-b+c-d)
={a+(b-c+d)}{a-(b-c+d)}
=a²-(b-c+d)²
=a²-(b²+c²+d²-2bc+2bd-2cd)
=a²-b²-c²-d²+2bc-2bd+2cd
Users viewing this question
are also looking at these questions 😉
