Mathematics
Senior High
Solved
計算の仕方がわかりません。数Bです!
731
1
□40 恒等式
S=
(3k-1)(3k+2)
3
3
22/5+508
1
-
n
=
3k-1 3k+2
を用いて,次の和Sを求めよ
3
・+
+......+
3
8・11
(3n-1)(3n+2)
3K-1
34+2
3nta
3442
2(372) 2 (3472)
・(3))
6hx4÷3m+2
6m4÷3n+2
24t2
2ht
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉

ありがとうございます!!
やってみます!