Mathematics
Senior High
Solved
なぜ初項が1なのかがわかりません、よろしくお願いします🙇♀️
□ 59 次の和を求めよ。
n
j-1
(1)*(-)*~*~
2
D}'
B
j-1
n-1
=
(1)
1+
+・・・+
2
2
j=1
2
2
+(1+8)(1+au
+5}
2'
これは,初項 1, 公比-1 項数nの等比数列の和を表すから
n
j=1
(-/-)
j-1
1.{1-(-1/2)"}
2
2
1-1-1
3
{(-)-
2
(++++
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