Mathematics
Senior High
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数Bの途中式です。
2行目から3行目にかけての式を詳しくお願いします!
(4)−S=1+3(2+2+2+......+2″-1)-(3-2) 2"
=1+3{
2.(2-1_1)]
2-1
したがって列S=(3n-5)・2"+5
1)] -(3-2)-2"
=-(3n-5).2"-5 10-58=
(1) ar
1
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わかりました!ありがとうございます