✨ Best Answer ✨
(2)x^3 + x^2y + x^2 − y
=(x^2 −1)y + x^3 + x^2
=(x+1)(x−1)y + x^2 (x+1)
=(x+1)(x^2 +xy−y)
(3)x^2 +(2y+1)x+y^2 +y
=x^2 +(2y+1)x+y(y+1)
=(x+y)(x+y+1)
(3)の2〜3行目で、たすき掛けを使っています。
多分こんな感じだと思います。
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