原子量
Al=27
S=32
O=16
より、
Al2(SO4)3=27・2+3・(32+4・16)
=54+3・(32+64)=54+3・96=342
になります！
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原子量
Al=27
S=32
O=16
より、
Al2(SO4)3=27・2+3・(32+4・16)
=54+3・(32+64)=54+3・96=342
になります！
Users viewing this question
are also looking at these questions 😉
