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α≠0に注意して両辺α^2で割ると
1+β/α+(β/α)^2=0
よって、β/α=(-1+√3i)/2または(-1-√3i)/2
極座標に直すと△OABは正三角形とわかり、|α-β|=3より面積は3×3×sin60°×(1/2)
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