(-1/2)sin(2x)+(1/2)cos(2x)
=(√2/2){(-1/√2)sin(2x)+(1/√2) cos(2x)}
= (√2/2)sin{2x+(3/4)π}
[∵sin(α+β)=sinαcosβ+cosαsinβ]
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(-1/2)sin(2x)+(1/2)cos(2x)
=(√2/2){(-1/√2)sin(2x)+(1/√2) cos(2x)}
= (√2/2)sin{2x+(3/4)π}
[∵sin(α+β)=sinαcosβ+cosαsinβ]
Users viewing this question
are also looking at these questions 😉
ありがとうございます！