✨ Best Answer ✨
y=x²-2ax+a²-4
y={x-(a+2)}{x-(a-2)}
x軸との交点(a-2,0),(a+2,0)
よって、(a+2)-(aー2)=4
✨ Best Answer ✨
y=x²-2ax+a²-4
y={x-(a+2)}{x-(a-2)}
x軸との交点(a-2,0),(a+2,0)
よって、(a+2)-(aー2)=4
Users viewing this question
are also looking at these questions 😉