1+2+......+n=n(n+1)/2
なので
Σ[k=1,n]k(k+1)/2
が求めたい式の値となります
1/2×Σ[k=1,n](k^2+k)
=1/2×( n(n+1)(2n+1)/6+n(n+1)/2 )
=1/12×n(n+1)( 2n+1+3 )
=1/6 n(n+1)(n+2)
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