一度ばらしてから、a,b,cのどれかでまとめます。
ab(a - b) + bc(b - c) + ca(c - a)
= a²b - ab² + b²c - bc² + c²a - ca²
= (b - c)a² - (b² - c²)a + b²c - bc²
= (b - c)a² - (b - c)(b + c)a + bc(b - c)
= (b - c){a² - (b + c)a + bc}
= (b - c)(a - b)(a - c)
= -(a - b)(b - c)(c - a)