Mathematics
Senior High
anを求める続きがわかりません。教えてください。
(3) Sn=3(-2)-3
(i) n = /αr =
(ii)n=2のとき、
anz
A₁ = S₁ =
3
+1
= Su-Sn-1
= 3-(-2)^-3
-3-(-2)
=3-(-2) "²³-3-(-2)^²-4
(n-3)-/
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