Mathematics
Senior High
Solved
この問題全く理解できません。
誰か教えてください。
S20
d
x
F²\x) = = (s" c'dt + ["te'ds)
X et t+Ste'dt)
dx
0
428 (1) F'(x) =
test
= Se'dt + x² + x¹ = [e'] + 2xe¹
xe
xe
= 2xe* + e* - 1
428 次の関数をxについて微分せよ。
(1) F(x)=√(x+te'dt
0
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理解できました
ありがとうございます!