Mathematics
Senior High
この問題の考え方を教えてほしいです。
[2 100 以下の自然数のうち、6の倍数または8の倍数である数の個数を求めよ。
U = 100
A = {6.1,6.2₁6.3 6.16}
B = { 8.1 8.2 8.3 8-12}
n (AUB) = n(A) + KCB) - (ANB).
16 + 12 =
24個
936
A
26
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