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△OACが二等辺三角形なので、∠OAC=∠OCA=α
△ABCの内角の和が180°より
α×2+18°×2+22°×2=180°
これを解くと、α=50°
Mathematics
Senior High
Resolved
αを求める問題です。どなたか式の解説お願いします😭😭🙏🏻
22 (₁) 22 +18°x 2 + 22° x 2 = 180°
2d +36° +49° = 180°
2α = 100°
2 = 50°
780
2220
180
A
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なるほど！ありがとうございます😭😭🙏🏻