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項の係数の求め方を教えてください

02 指定された頃の係数を求めよ。 (10点×2) (2) (2x-y-5z) [x2y2z2]

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✨ Best Answer ✨

多項定理をつかいましょう!
多項定理の公式
n!/p!q!r! a^p b^q c^r(n=p+r+q)
解き方
6!/2!2!2! ×(2x)²(-y)²(-5z)²=6!/8×(4x²)(y²)(25z²)
=9000x²y²z² 答え9000

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