Mathematics
Senior High

教えてください。

Answers

(1)log(2)16/log(2)8
=log(2)2⁴/log(2)2³
=4/3

( 2) log[1/2]8
=log[2]8/log[2]1/2
=log[2](2^3)/log[2]{2^(-1)}
=3log[2]2/(-log[2]2)
=3/(-1)
=-3

(3) log9_√3
=log9_(3^(1/2))
=log9_(9^(1/4))
=1/4

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