Answers
(a + b)(b + c)(c + a) + abc
= (a²b + a²c + b²a + b²c + c²a + c²b + 2abc) + abc
= (a + b)c² + (a² + b² + 3ab)c + ab(a + b)
= (c + a + b)((a + b)c + ab)
= (a + b + c)(ab + bc + ca)
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