Answers
Answers
(x^2-3x+4)(x^2+3x+4)
=(x^2+4-3x)(x^2+4+3x)
x^2+4=Aとする
=(A-3x)(A+3x)
=A^2-9x^2
=(x^2+4)^2-9x^2
=x^4+8x^2+16-9^2
=x^4-x^2+16
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