(1)BC
=ABsinθ
=ksinθ
(2)AC
=ABcosθ
=kcosθ
(3)AD
=ACcosθ
={kcosθ}cosθ
=kcos²θ
(4)CD
=ACsinθ
={kcosθ}sinθ
=ksinθcosθ
(5)BD
=AB-AD
=k-kcos²θ
=k(1-cos²θ)
=ksin²θ
★BD
=BCsinθ
={ksinθ}sinθ
=ksin²θ
(1)~(5)全て分かりません🙇♀️答えと解き方の解説お願いします
(1)BC
=ABsinθ
=ksinθ
(2)AC
=ABcosθ
=kcosθ
(3)AD
=ACcosθ
={kcosθ}cosθ
=kcos²θ
(4)CD
=ACsinθ
={kcosθ}sinθ
=ksinθcosθ
(5)BD
=AB-AD
=k-kcos²θ
=k(1-cos²θ)
=ksin²θ
★BD
=BCsinθ
={ksinθ}sinθ
=ksin²θ
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