✨ Best Answer ✨
条件式の両辺を底10で対数を取ると
alog₁₀321=3,blog₁₀3210=3
∴a=3/log₁₀321,b=3/log₁₀3210
∴1/a=log₁₀321/3,1/b=log₁₀3210/3
∴1/a-1/b=(log₁₀321-log₁₀3210)/3=log₁₀10⁻¹/3=-1/3
✨ Best Answer ✨
条件式の両辺を底10で対数を取ると
alog₁₀321=3,blog₁₀3210=3
∴a=3/log₁₀321,b=3/log₁₀3210
∴1/a=log₁₀321/3,1/b=log₁₀3210/3
∴1/a-1/b=(log₁₀321-log₁₀3210)/3=log₁₀10⁻¹/3=-1/3
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