計算ミスしていなければ、
A+B = (ax-b/x) + (bx-a/x) = (a+b)(x-1/x) = 3*2 = 6
AB = (ax-b/x)(bx-a/x) = ab(x²+1/x²)-(a²+b²)
=ab{(x-1/x)²+2}-{(a+b)²-2ab}
=1*(2²+2)-(3²-2*1)=6-7= -1
∴ A+B=6,AB=-1
B²/A + A²/B = (A³+B³)/AB
= {(A+B)³-3AB(A+B)}/AB
= {6³-3*(-1)*6}/(-1) = -234