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請問 我的理解問題出在哪呢？ 令z1輻角 為theta z2 幅角theta +120度 因為z2取共軛 和 z2對稱x軸 所以「z2取共軛之輻角為theta+240度」 但為什麼 -theta-120度 和 theta+240度 非同界角？
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請問 選項五的複數w會落在哪裡呢？ 我的理解是 因為複數z和 w 以及-w的距離一樣 又-w為w對稱原點 所以 滿足條件的z只能在x軸上 又因為z不是零複數 所以 z只能在(2,0) 但我不知道w的位置會落在哪裡 （如果是以向量理解的話 w z 所圍面積會是矩形 所以z 向量和w向量垂直 這樣用向量解我可以理解
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請問 這題我的做法是正確的嗎 還是只能以投影概念解 令斜角坐標系（坐標以走幾個AB AC向量理解 不考慮實際長度） ： A為原點 B坐標為 （1,0) C為（0,1) O點坐標為（x y ) 又 x y 滿足x+2y=1 所以外心O在該直線上 又因為 過頂點B 所以三角形為等腰三角形 即可求角BAC
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想請問第二小題 謝謝！！
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請問進階題的第二題
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如果函數圖形長這樣 題目求的是函數小於0 那麼答案要寫無解還是無實數解？
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謝謝
多試幾遍就會啦~
是放尺在下面這樣嗎 因為很想學
謝謝哦😂 因為我寫字習慣用尺 這樣會比較整齊😎
這是自己寫的嗎 太整齊了吧