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問這題！
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請問 這題我的做法是正確的嗎 還是只能以投影概念解 令斜角坐標系（坐標以走幾個AB AC向量理解 不考慮實際長度） ： A為原點 B坐標為 （1,0) C為（0,1) O點坐標為（x y ) 又 x y 滿足x+2y=1 所以外心O在該直線上 又因為 過頂點B 所以三角形為等腰三角形 即可求角BAC
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