✨ Best Answer ✨
k(k+1)(k+2)=1/4[k(k+1)(k+2){(k+3)-(k-1)}]
=1/4{k(k+1)(k+2)(k+3)-(k-1)k(k+2)(k+3)}
あとは考えてみてください!
✨ Best Answer ✨
k(k+1)(k+2)=1/4[k(k+1)(k+2){(k+3)-(k-1)}]
=1/4{k(k+1)(k+2)(k+3)-(k-1)k(k+2)(k+3)}
あとは考えてみてください!
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