Mathematics
Senior High
途中式を教えていただきたいです。
a+b=c......①
ab = 2c + 2...･・・②
10b = a +2c...... ③
①を②に代入
ab = 2a + 26+2・・・・・・ ④
① を ③ に代入
10b= a + 2a + 2b
8b = 3a......5
④を3倍した式に ⑤ を代入
3ab = 6a +66 +6
862 = 166 +66 +6
462-116-3= (46+1)(6-3)=0
bは整数だから、6=3
⑤より、 α = 8
さらに①より、c=8+3=11
よって、 a + b + c = 8 +3 + 11 = 22
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