Mathematics
Senior High
数学BのΣの問題です。
この問題の解き方が全く分かりません。
解き方を教えて頂けると嬉しいです。
·n
n
(4) Σ(k³-4k) = Σ k³ −4Σ k
3
k=1
k=1
n
=
k=1
2
= {{\n(n+1)} ² − 4 •_ _{n{n+ 1) =)=¹6
-
2
=1/12m2(n+1)2-4.1/12n(n+1)
=
n(n+1)
-
(n+1){n(n+1)-8}
n(n+
∙n(n+1)(n²+n-8)
2482
*
n
(2-2) (+)
k=1
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