Mathematics
Senior High
数Ⅲ不定積分の問題です。
どうして積分定数がC'になるのかがわかりません。また、Cを-3/2+C'と置き換えるのも分かりません。
教えてください!お願いします!
(10) x log(x+3) dx
2xdx=dt
(log(x²+3)}. (2x)dx
log tdt= (logt)-(tydt
(10) x2+3=t とおくと
S xlog (x²+3) dx =
=
= {(logt)-t-(logty-tdt}
=(tlog t-t) + C'
=(x²+3)log (x²+3)(x²+3)+C'
- 12/2+C'=Cとおき換えて
Salog (x¹+3ids-¹+30log(+3)+0
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