Mathematics
Senior High
同じxを求めているのに解が違くなってしまいます。原因はなんなのでしょうか？
50/6 450
Coo
x
60⁰
45° 2 Auzil
( 100 )² = (S0√6 ) ³ +^x²³²-2-50√6-x
x² =100√3x + 5000
解の公式を使う。
x= 50√13 + 50.
Ⓒ 60°3 uz 42²
(50√6) ² = x²³² + 100² - 200- 100 c05600
X
1² 100x-5000 =
解の公式を使う.
X = 50 ± 50√3
Date
IL
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