Mathematics
Senior High
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B
(1) 放物線y=2x²-3x+4.① をx軸方向に -1, y 軸方向に3だけ平行移動したときの放物線
の方程式を求めよ｡
(2) (1)で求めた放物線を原点に関して対称に移動したときの放物線の方程式を求めよ。
2x²=7x+6
(XY+ 3 = 2(x-1) ² - 3(²-1) + 4
9₁3=2(x²-2x+1)-3x+3 +4 9-3=2(2+1)-3(201),
7 = 2x²³²+x+6
3+3 = 2₂²²=4x²+2x+1
3 = 2x²-7x+6
y = -2x = 7x-6
2x77x-6
7=-2x+2-6
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