✨ Best Answer ✨
∫[-1→1](x+2)^2dx-∫[-1→1](x-2)^2dx
=[1/3(x+2)^3](-1→1)-[1/3(x-2)^3](-1→1)
=0
です。
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✨ Best Answer ✨
∫[-1→1](x+2)^2dx-∫[-1→1](x-2)^2dx
=[1/3(x+2)^3](-1→1)-[1/3(x-2)^3](-1→1)
=0
です。
Users viewing this question
are also looking at these questions 😉
